Adjusting values based on the frequency of occurrences

When the user inputs 110 into the quantity field, and there are 20 pieces in the multiplicity, the system should automatically recalculate the quantity to be 120 pieces.

For instance, if the multiplicity is 100 and the customer requires 1010 pieces, entering 1010 into the quantity field should result in a recalculated value of 1100 pieces.

I require rounding up based on the item's multiplicity.

curValue = Math.floor(Math.ceil((curValue * this.precisionFactor )/this.precisionFactor))

Answer №1

To accomplish this task in the most straightforward manner, consider determining the number of 'batches' based on the given multiplicity. Round up to the nearest whole number and then multiply by the multiplicity once more. Here is the function:

function calculateTotal(amount, batchSize) {
  // round up to full batches
  let numBatches = Math.ceil(amount/batchSize);
  
  // return the total quantity
  let total = numBatches * batchSize;
  return total;
}

While it can be condensed into a single line, I opted for a clearer explanation with multiple lines.

Answer №2

let startingValue = 105;
let incrementValue = 20;

let additionalAmount = 0;
for (let x = startingValue; x >= incrementValue; x -= incrementValue ) {
    let tempVal = x - incrementValue;
    additionalAmount = incrementValue - tempVal;
}

console.log("updated value: " + (startingValue + additionalAmount))

Answer №3

To calculate the rounded up value based on multiplicity, divide the given number by the multiplicity and use Math.floor() to get the integer part. Add 1 to this integer part and then multiply it by the multiplicity to get the final result.

function roundUpValue(inputValue, multiplier){
  return multiplier*(Math.floor(inputValue/multiplier) + 1);
}

console.log(roundUpValue(105, 20));
console.log(roundUpValue(1010, 100));

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