Add the appropriate ordinal suffixes ('-st', '-nd', '-rd', '-th') to each item based on its index

Question

Add the appropriate ordinal suffixes ('-st', '-nd', '-rd', '-th') to each item based on its index

Imagine having an array filled with various option values, such as:

var options = ["apple", "banana", "cherry", "date", "elderberry", "fig", "grapefruit", "honeydew", "kiwi", "lemon", "mango", "nectarine", "orange", "pear", "quince", "raspberry", "strawberry", "tangerine", "ugli fruit", "vanilla bean", "watermelon", "ximenia", "yellow plum", "zucchini"];

If there was a need to convert these into formatted strings that include their position in the array, like this:

var result = ['1st option is "apple"', '2nd option is "banana", '3rd option is "cherry"', '4th option is "date"',...];

An attempt has been made to achieve most of it using the following code:

var result = [];
for(var i = 0; i < options.length; i++){
    result.push((i+1)+' option is "'+options[i]+'"');
}

This code generates strings similar to 1 option is "apple". However, adding the correct suffixes ('st', 'nd', 'rd', 'th') based on the position remains a challenge. Assistance in resolving this issue would be greatly appreciated. Thank you!

javascript arrays string

Answer 1

Answer №1

One way to handle suffixes is by storing them in an array and matching them with the corresponding index:

const arr = [...'abcdefghijklmnopqrstuvwxyz'];
const suffixes = ['th', 'st', 'nd', 'rd'];

const result = arr.map((item, i) => 
  (idx = ~~(i % 10) + 1 > 3 || ~~(i / 10) == 1 ? 0 : ~~(i % 10) + 1, 
  `${i+1}-${suffixes[idx]} options is '${item}'`));

console.log(result);

.as-console-wrapper {min-width: 100%}

Answer 2

One way to handle suffixes is by storing them in an array and matching them with the corresponding index:

const arr = [...'abcdefghijklmnopqrstuvwxyz'];
const suffixes = ['th', 'st', 'nd', 'rd'];

const result = arr.map((item, i) => 
  (idx = ~~(i % 10) + 1 > 3 || ~~(i / 10) == 1 ? 0 : ~~(i % 10) + 1, 
  `${i+1}-${suffixes[idx]} options is '${item}'`));

console.log(result);

.as-console-wrapper {min-width: 100%}

Answer 3

Answer №2

Give this Code a try – it's effective:

https://en.wikipedia.org/wiki/Ordinal_indicator#English

-st is utilized for numbers that end in 1 (e.g. 1st, pronounced first)

-nd is utilized for numbers that end in 2 (e.g. 92nd, pronounced ninety-second)

-rd is utilized for numbers that end in 3 (e.g. 33rd, pronounced thirty-third)

An exception to the above rules is seen with all "teen" numbers ending in 11, 12, or 13 which use -th (e.g. 11th, pronounced eleventh, 112th, pronounced one hundred [and] twelfth)

-th is used for all other numbers (e.g. 9th, pronounced ninth).

var arr = ["a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z"];

function addSuffix(i) {
    var j = i % 10,
        k = i % 100;
    if (j == 1 && k != 11) {
        return i + "-st";
    }
    if (j == 2 && k != 12) {
        return i + "-nd";
    }
    if (j == 3 && k != 13) {
        return i + "-rd";
    }
    return i + "-th";
}

var result = [];
for (var i = 0; i < arr.length; i++) {
    result.push(`${addSuffix(i + 1)} option is  '${arr[i]}'`);
}
console.log(result);

Answer 4

Give this Code a try – it's effective:

https://en.wikipedia.org/wiki/Ordinal_indicator#English

-st is utilized for numbers that end in 1 (e.g. 1st, pronounced first)

-nd is utilized for numbers that end in 2 (e.g. 92nd, pronounced ninety-second)

-rd is utilized for numbers that end in 3 (e.g. 33rd, pronounced thirty-third)

An exception to the above rules is seen with all "teen" numbers ending in 11, 12, or 13 which use -th (e.g. 11th, pronounced eleventh, 112th, pronounced one hundred [and] twelfth)

-th is used for all other numbers (e.g. 9th, pronounced ninth).

var arr = ["a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z"];

function addSuffix(i) {
    var j = i % 10,
        k = i % 100;
    if (j == 1 && k != 11) {
        return i + "-st";
    }
    if (j == 2 && k != 12) {
        return i + "-nd";
    }
    if (j == 3 && k != 13) {
        return i + "-rd";
    }
    return i + "-th";
}

var result = [];
for (var i = 0; i < arr.length; i++) {
    result.push(`${addSuffix(i + 1)} option is  '${arr[i]}'`);
}
console.log(result);

Answer 5

Answer №3

If you need a function to determine the suffix for numbers, you can utilize the modulo operator %. Here is an example of how such a function could be implemented:

function findSuffix(num) {
    let remainder = num % 10;

    if(remainder === 1 && num != 11) { return 'st'; }
    else if(remainder === 2 && num != 12) { return 'nd'; }
    else if(remainder === 3 && num != 13) { return 'rd'; }
    else { return 'th'; }
}

You can use this function in combination with a loop to add the appropriate suffix to each number in an array:

var finalResult = [];
for(var n = 0; n < array.length; n++){
    finalResult.push((n+1) + "-" + findSuffix(n+1) + " option is "'+array[n]+'"');
}

Answer 6

If you need a function to determine the suffix for numbers, you can utilize the modulo operator %. Here is an example of how such a function could be implemented:

function findSuffix(num) {
    let remainder = num % 10;

    if(remainder === 1 && num != 11) { return 'st'; }
    else if(remainder === 2 && num != 12) { return 'nd'; }
    else if(remainder === 3 && num != 13) { return 'rd'; }
    else { return 'th'; }
}

You can use this function in combination with a loop to add the appropriate suffix to each number in an array:

var finalResult = [];
for(var n = 0; n < array.length; n++){
    finalResult.push((n+1) + "-" + findSuffix(n+1) + " option is "'+array[n]+'"');
}

Answer 7

Answer №4

Give this a shot:

const  array= ["apple", "banana", "cherry", "date", "elderberry", "fig", "grape", "honeydew", "iceberg lettuce", "jackfruit", "kiwi", "lemon", "mango", "nectarine", "orange", "pear", "quince", "raspberry", "strawberry", "tangerine", "ugli fruit", "vanilla bean", "watermelon", "ximenia caffra", "yellow passion fruit", "zucchini"];

const suffix = (num) => (["st","nd","rd"][((num+90)%100-10)%10-1] || "th")

const output  = array.map((val,i)=> `${i+1}-${suffix(i+1)} choice is '${val}'`);

console.log(output);

Answer 8

Give this a shot:

const  array= ["apple", "banana", "cherry", "date", "elderberry", "fig", "grape", "honeydew", "iceberg lettuce", "jackfruit", "kiwi", "lemon", "mango", "nectarine", "orange", "pear", "quince", "raspberry", "strawberry", "tangerine", "ugli fruit", "vanilla bean", "watermelon", "ximenia caffra", "yellow passion fruit", "zucchini"];

const suffix = (num) => (["st","nd","rd"][((num+90)%100-10)%10-1] || "th")

const output  = array.map((val,i)=> `${i+1}-${suffix(i+1)} choice is '${val}'`);

console.log(output);

Add the appropriate ordinal suffixes ('-st', '-nd', '-rd', '-th') to each item based on its index

Answer №1

Answer №2

Answer №3

Answer №4

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