I need to create a similar function in JAVA, but I'm struggling to understand the role of -Infinity in JAVA and how it can be utilized.
Here is the code snippet in JS:
function arrayMax(arr) {
var len = arr.length,
max = -Infinity;
var rangomax=99999;
while (len--) {
if ((Number(arr[len]) > max)&&(Number(arr[len])<rangomax)) {
max = Number(arr[len]);
}
}
return max;
}
Give this a shot:
public double findLargestNumberInArray(double[] numbers){
int length = numbers.length;
double maxNumber = Double.NEGATIVE_INFINITY;
double rangeMax = 99999;
while(length--){
if ((numbers[length] > maxNumber) && (numbers[length] < rangeMax)) {
maxNumber = numbers[length];
}
}
return maxNumber;
}
To achieve Java code that closely resembles JavaScript code, disregarding undefined and null values, it is best to assume that the input is an Object[], as indicated by the numerous Number() calls.
public static double arrayMax(Object... arr) {
double rangomax = 99999;
double max = Double.NEGATIVE_INFINITY;
for (Object obj : arr) {
double value = number(obj);
if (value > max && value < rangomax) {
max = value;
}
}
return max;
}
// Function similar to JavaScript's Number()
private static double number(Object obj) {
if (obj instanceof Number) {
return ((Number) obj).doubleValue();
}
try {
return Double.parseDouble(obj.toString());
} catch (NumberFormatException e) {
return Double.NaN;
}
}
You may also consider creating overloads for primitive values, such as:
public static double arrayMax(double... arr) {
double rangomax = 99999;
double max = Double.NEGATIVE_INFINITY;
for (double value : arr) {
if (value > max && value < rangomax) {
max = value;
}
}
return max;
}
An easy method to determine the highest value in an array:
public Double findMaxValue(int[] values) {
double maxValue = Double.MIN_VALUE;
for (int index = 0; index < values.length; index++){
if (values[index] > maxValue) {
maxValue = values[index];
}
}
return maxValue;
}
One suggested solution is to utilize Integer.MIN_VALUE to find the maximum value in an array. However, there are alternative methods that do not rely on Integer.MIN_VALUE.
public int max(int[] arr){
if(arr == null || arr.length == 0) {
return 0; // Handle empty or null arrays by returning a default value
}
int max = arr[0];
for(int num: arr){
if(num >= max){
max = num;
}
}
return max;
}
Note: This method can also be applied to double[] arrays.
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