A guide on finding identical objects in two separate arrays using JavaScript

Question

A guide on finding identical objects in two separate arrays using JavaScript

Is there a way to achieve the following?

const array1 = [{data1}, {data2},{data3}] 
const array2 = [{data1}, {data4},{data5}]

The desired output is:

{data1}

javascript arrays object intersection

Answer 1

Answer №1

This method is suitable for basic objects, but keep in mind that it may not be effective for properties based on functions.

const array1 = [{a:1}, {b:2},{c:3}] 
const array2 = [{a:1}, {d:4},{e:5}]

const array1Stringify = array1.map(el => JSON.stringify(el));
const array2Stringify = array2.map(el => JSON.stringify(el));

const result = array1Stringify.filter(el => array2Stringify.includes(el)).map(el => JSON.parse(el));

console.log(result);

Answer 2

This method is suitable for basic objects, but keep in mind that it may not be effective for properties based on functions.

const array1 = [{a:1}, {b:2},{c:3}] 
const array2 = [{a:1}, {d:4},{e:5}]

const array1Stringify = array1.map(el => JSON.stringify(el));
const array2Stringify = array2.map(el => JSON.stringify(el));

const result = array1Stringify.filter(el => array2Stringify.includes(el)).map(el => JSON.parse(el));

console.log(result);

Answer 3

Answer №2

In order to solve your issue, the key factor lies in determining the criteria for evaluating equality between your objects. Once you have this defined, comparing one array against another will reveal the desired matches. One of the most straightforward and easily understandable methods involves using a nested loop structure.

let list1 = ['apple', 'banana', 'orange'] 
let list2 = ['apple', 'kiwi', 'grape']

let matchingItems = [];
for (let x = 0; x < list1.length; x++) {
    for (let y = 0; y < list2.length; y++) {
        if (list1[x] === list2[y]) { //considering object equality here
            matchingItems.push(list1[x]);
        }
    }
}

console.log({matchingItems});

Answer 4

In order to solve your issue, the key factor lies in determining the criteria for evaluating equality between your objects. Once you have this defined, comparing one array against another will reveal the desired matches. One of the most straightforward and easily understandable methods involves using a nested loop structure.

let list1 = ['apple', 'banana', 'orange'] 
let list2 = ['apple', 'kiwi', 'grape']

let matchingItems = [];
for (let x = 0; x < list1.length; x++) {
    for (let y = 0; y < list2.length; y++) {
        if (list1[x] === list2[y]) { //considering object equality here
            matchingItems.push(list1[x]);
        }
    }
}

console.log({matchingItems});

Answer 5

Answer №3

Consider using this solution, which requires either an id or a specific object key value for comparison:

Answer 6

Consider using this solution, which requires either an id or a specific object key value for comparison:

Answer 7

Answer №4

Is there a specific purpose behind using curly brackets in this scenario? I have provided a potential solution for your inquiry that you may find beneficial.

const obj1 = {a: 'foo1', b: 'bar1'};
const obj2 = {a: 'foo2', b: 'bar2'};
const obj3 = {a: 'foo3', b: 'bar3'};
const obj4 = {a: 'foo4', b: 'bar4'};
const obj5 = {a: 'foo5', b: 'bar5'};

let array1 = [obj1, obj2, obj3] 
let array2 = [obj1, obj4, obj5]

let result = array1.filter(o1 => array2.some(o2 => o1 === o2));

console.log(result);

If you require a thorough object comparison for each object, I recommend checking out this detailed solution.

Answer 8

Is there a specific purpose behind using curly brackets in this scenario? I have provided a potential solution for your inquiry that you may find beneficial.

const obj1 = {a: 'foo1', b: 'bar1'};
const obj2 = {a: 'foo2', b: 'bar2'};
const obj3 = {a: 'foo3', b: 'bar3'};
const obj4 = {a: 'foo4', b: 'bar4'};
const obj5 = {a: 'foo5', b: 'bar5'};

let array1 = [obj1, obj2, obj3] 
let array2 = [obj1, obj4, obj5]

let result = array1.filter(o1 => array2.some(o2 => o1 === o2));

console.log(result);

If you require a thorough object comparison for each object, I recommend checking out this detailed solution.

A guide on finding identical objects in two separate arrays using JavaScript

Answer №1

Answer №2

Answer №3

Answer №4

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