I have a 2-dimensional array that contains both integers and strings, and I'm looking to eliminate duplicates from it:
original array =
[["admin", 2, "regular"], ["customer", "regular"], ["regular", "customer"], [1], ,["admin"], [1], ["admin"]desired outcome =
[["admin", 2, "regular"], ["customer", "regular"], [1], ["admin"]]Can anyone suggest how I can achieve this using JavaScript?
Is it significant if the arrangement of your array (and its sub-arrays) changes? If not, then:
var arr = [["admin", 2, "regular"], ["customer", "regular"], ["regular", "customer"], [1],["admin"], [1], ["admin"]];
arr = arr.map(x => x.sort()).sort();
var uniqueArr = [];
uniqueArr.push(arr[0]);
for (var j = 1; j < arr.length; j++){
if (JSON.stringify(arr[j]) != JSON.stringify(arr[j-1])){
uniqueArr.push(arr[j]);
}
}
console.log(uniqueArr);One way to achieve uniqueness is by sorting a copy of the inner arrays, creating a string representation, and then comparing against a hash table while filtering.
var array = [["admin", 2, "regular"], ["customer", "regular"], ["regular", "customer"], [1], ["admin"], [1], , ["admin"]],
object = Object.create(null),
unique = array.filter(function (a) {
var b = a.slice().sort().join('|');
return !object[b] && (object[b] = true)
});
console.log(unique);.as-console-wrapper { max-height: 100% !important; top: 0; }Check out this non-JavaScript algorithm that I came up with for you. It may not differentiate between ["customer", "regular"] and ["regular", "customer"], but it should give you a general idea:
var uniqueArray = [];
for(item in originalItems) { //iterate through the original array
var isUnique = 1; //flag to check if item is already in uniqueArray
for(existingItem in uniqueArray) {
if(existingItem == item) isUnique = 0; //item is already in uniqueArray
}
if(isUnique == 1) uniqueArray += item; //add item if not already in uniqueArray
isUnique = 1; //reset flag value
}
In essence, this logic helps you create a new array with only unique values. Good luck with your coding endeavors :)
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