A function that takes one argument and performs named destructuring operations

Question

Is it possible to classify a function like this as a unary function?

function unaryOrNot([foo,bar,baz,...args,]){}

When given an input such as:

[1,2,3,4,5,6,7,8,9]

Even though there is technically only one input, I still have named access to foo, bar, and baz, which are the first three properties of the array.

I appreciate your responses!

Answer 1

Answer №1

The operation is considered unary, meaning it operates on only one argument.

To clarify further, you could express the operation in a different way:

function operateUnary(arg) {
  const [first, second, third,...rest] = arg;
  //...
}

Whether you destructure the input argument or not doesn't affect the overall function definition.

You could even consider writing it as:

function operateUnary() {
  const [first, second, third,...rest] = arguments[0];
  //...
}

If you're feeling bold, feel free to submit this for a code review! (Go ahead, I challenge you ;))

Answer 2

The operation is considered unary, meaning it operates on only one argument.

To clarify further, you could express the operation in a different way:

function operateUnary(arg) {
  const [first, second, third,...rest] = arg;
  //...
}

Whether you destructure the input argument or not doesn't affect the overall function definition.

You could even consider writing it as:

function operateUnary() {
  const [first, second, third,...rest] = arguments[0];
  //...
}

If you're feeling bold, feel free to submit this for a code review! (Go ahead, I challenge you ;))