Can anyone assist me in combining these two ternary operators into a single expression?
var longest = a.length > b.length ? a : b;
var shortest = a.length > b.length ? b : a;
Much appreciated!
Can anyone assist me in combining these two ternary operators into a single expression?
var longest = a.length > b.length ? a : b;
var shortest = a.length > b.length ? b : a;
Much appreciated!
In JavaScript 1.7 (now it's 1.8.5), you have the option to use Destructuring assignment.
It's worth noting that cross-browser compatibility is limited, but for educational purposes, I will provide this information as part of the response.
Declaring both variables in the expression makes it impossible.
Instead of nesting the first expression as a condition within the second, it might be better to keep them as separate lines to maintain clarity in your code. In this scenario, there is no benefit in optimizing with nested ternaries as it does not provide any performance enhancements.
One straightforward approach for handling the two values could involve a method like the following (syntax adjustments may be necessary):
[min, max] = [a, b].sort(function(a, b) {return a.length > b.length});
Although this question has already been answered, I decided to give it a try just for fun.
shorter = ((a.length < b.length) && (longer = b))||((longer = a)&&false) ? a: b;
UPDATE:
Thanks to the suggestion from @MattWhipple, you can actually make this code shorter (you may encounter a warning in the console)
((a.length < b.length) && (shorter = a) && (longer = b)) || ((shorter = b) && (longer = a))
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